36, 37 and 38.
They are 1986, 1987 and 1988.
They are: 57+58+59 = 174
65/67/69
The numbers are 121, 122 and 123.
87
-1, -3, -5
258/3 = 86 so the answer has to be 84+86+88
36, 37 and 38.
They are 1986, 1987 and 1988.
129 divided by 3 is 43, so the 3 consecutive integers having a sum of 129 are 42, 43, and 44.
They are: 57+58+59 = 174
65/67/69
The numbers are 121, 122 and 123.
84 / 3 = 28... therefore the answer is... 27, 28 & 29
17 + 19 + 21 = 57
33