The answer is 64 4^3 = 64 8^2 = 64
64. 64 = 82 = 43 26 = (23)2 = (22)3 = 64.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
121
Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.
The answer is 64 4^3 = 64 8^2 = 64
none, by definition a 3 digit number is greater than 99, thus "020" and "20.0" can not be a 3 digit number
64. 64 = 82 = 43 26 = (23)2 = (22)3 = 64.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
121
That number times itself twice. Ex. 4^3= 4•4•4= 64
4,096 = (64)2 = (16)3
A two digit number whose two digits added together equal 42 and multiplied together equal 82
A smaller 3 digit number or a 2 digit number (99).
Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.
No. The smallest 2 digit number is 10 the smallest 3 digit number is 100 - so the question is whether (100-10) is a perfect square? No - 90 is not a perfect square. 8x8 is 64 and 9x9 is 91, not 90.
9999 is the 4-digit number and 999 is the 3-digit number.