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The number is abcd
(1) a=2b
(2) d=a+b-2
(3) a+b+c+d=15

substituting eq. 1 into eq. 2
d=2b+b-2
d=3b-2

Now, equation 3 is
2b+b+c+3b-2=15
6b+c-2=15
6b+c=17
Only possible answer for (b,c) is (2,5)

a=2b ► a=4
b=2
c=5
d=a+b-2 ► d=4+2-2 ►d=4

The answer is 4254 ■

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