The number is abcd
(1) a=2b
(2) d=a+b-2
(3) a+b+c+d=15
substituting eq. 1 into eq. 2
d=2b+b-2
d=3b-2
Now, equation 3 is
2b+b+c+3b-2=15
6b+c-2=15
6b+c=17
Only possible answer for (b,c) is (2,5)
a=2b ► a=4
b=2
c=5
d=a+b-2 ► d=4+2-2 ►d=4
The answer is 4254 ■
1339
this question doesnt make sense
The question cannot be answered. All that I know about your number is that is has at least 4 digits. Your number could be a hundred digits long - I have no way of knowing.
To round a number to the nearest thousand, first identify the hundreds digit (the third digit from the right). If this digit is 5 or greater, round up by adding 1 to the thousands digit and changing the digits to the right of it to zero. If the hundreds digit is less than 5, simply keep the thousands digit the same and change all digits to the right to zero.
The digit in the hundreds place of the number 1098 is 0. In the number 1098, the digits are arranged as follows: 1 in the thousands place, 0 in the hundreds place, 9 in the tens place, and 8 in the ones place.
1339
this question doesnt make sense
The question cannot be answered. All that I know about your number is that is has at least 4 digits. Your number could be a hundred digits long - I have no way of knowing.
To round a number to the nearest thousand, first identify the hundreds digit (the third digit from the right). If this digit is 5 or greater, round up by adding 1 to the thousands digit and changing the digits to the right of it to zero. If the hundreds digit is less than 5, simply keep the thousands digit the same and change all digits to the right to zero.
There is a lot of answer for this, but I tell you one. The answer is 6541.
The digit in the hundreds place of the number 1098 is 0. In the number 1098, the digits are arranged as follows: 1 in the thousands place, 0 in the hundreds place, 9 in the tens place, and 8 in the ones place.
The places are always the same no matter what the digits are. The value is obtained by multiplying the place times the digit. Starting from the right, the places in an 8-digit number are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions and ten millions.
The number 2637 has four digits. Each digit represents a place value: thousands, hundreds, tens, and units. Therefore, the digits are 2, 6, 3, and 7.
Since the first digit cannot be zero, the possibilities are 1054, 1216, or 3034.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27
25 digit numbers would be septillions.
The largest 5 all odd digit number is 99999, which makes the rest of the question meaningless. 59713 if you think the information is not meaningless