1133,
The largest 4-digit number with two different digits is 9998. Its successor is the next number, which is 9999. However, 9999 has only one digit (9), so we need to find the next valid 4-digit number with two different digits. This number is 10000, which is technically a 5-digit number, so the largest valid number with two different digits before 9999 is 9998, and its successor cannot be a 4-digit number with two different digits. Thus, there is no valid successor that meets the criteria.
To form a 3-digit number using the digits 1, 3, and 5, where each digit is used only once, we can arrange these three digits in different orders. The number of different arrangements of 3 digits is calculated as 3! (3 factorial), which is 3 × 2 × 1 = 6. Therefore, a total of 6 different 3-digit numbers can be formed using the digits 1, 3, and 5.
The greatest 5-digit number using 3 different digits is 99987. This number is formed by using the digit '9' three times, along with '8' and '7' to maximize the overall value while adhering to the condition of using only three different digits. Other combinations, like 99876 or 99875, do not yield a higher number while still using only three distinct digits.
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Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
The largest 4-digit number with two different digits is 9998. Its successor is the next number, which is 9999. However, 9999 has only one digit (9), so we need to find the next valid 4-digit number with two different digits. This number is 10000, which is technically a 5-digit number, so the largest valid number with two different digits before 9999 is 9998, and its successor cannot be a 4-digit number with two different digits. Thus, there is no valid successor that meets the criteria.
To form a 3-digit number using the digits 1, 3, and 5, where each digit is used only once, we can arrange these three digits in different orders. The number of different arrangements of 3 digits is calculated as 3! (3 factorial), which is 3 × 2 × 1 = 6. Therefore, a total of 6 different 3-digit numbers can be formed using the digits 1, 3, and 5.
The greatest 5-digit number using 3 different digits is 99987. This number is formed by using the digit '9' three times, along with '8' and '7' to maximize the overall value while adhering to the condition of using only three different digits. Other combinations, like 99876 or 99875, do not yield a higher number while still using only three distinct digits.
They are the same because they are both multiplication. They also can be the same if the two digit number times by the one digit number equals a three digit number. They are different because the 3 digits number will obviously produce a higher product.
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Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
There are only two smaller 3-digit numbers and both of them have repeated digits.
There is no number, no matter the number of digits, that is only divisible by 2.
There are only five distinct odd digits.
The number has only 5 digits: there are not 8 digits in it.