The full circle of the clock is 360 degrees. The distance between any two figures on the clock is therefore 360 ./. 12 = 30 degrees. When it's 6 o'clock there are six figures between the hour hand and the minute hand, so 6 x 30 = 180 degrees.
straight angle
Eight times in a day the hands of a clock form straight angle. At first they form straight angle when the hour amd minute hand are on 3 and 9 in noon and night. Second, when the hour amd minute hand are on 9 and 3 in morning and night. Third when the hour amd minute hand are on 12 and 6 At last when the hour amd minute hand are on 6 and 12.
Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is: minute_deg = minute * 360 / 60 = minute * 6; The hour hand will make a complete revolution every hour, so its formula is: hour_deg = hour * 360 / 12 = hour * 30; A function to find the angle would be: int angleBetweenHands(int hour, int minute) { if(hour > 12) // In case of 24 hour clock hour -= 12; int angle = hour * 30 - minute * 6; if(angle > 180) angle = 360 - angle; return(angle); }
Assuming the hour hand moves steadily for the entirety of the hour, the angle formed by the hour and minute hand would be 55 degrees.
At 4 o'clock, the minute hand is at the 12, and the hour hand is at the 4. Each hour mark on a clock represents 30 degrees (360 degrees divided by 12 hours). Therefore, the angle between the hour hand and the minute hand at 4 o'clock is 4 x 30 = 120 degrees.
straight angle
When it is 7:00, the hour hand and minute hand of a 12-hour clock form a 150° angle.
90 degrees
72.5°
Eight times in a day the hands of a clock form straight angle. At first they form straight angle when the hour amd minute hand are on 3 and 9 in noon and night. Second, when the hour amd minute hand are on 9 and 3 in morning and night. Third when the hour amd minute hand are on 12 and 6 At last when the hour amd minute hand are on 6 and 12.
10°, on a standard 12-hour clock. The minute hand is pointing at the 4, but the hour hand has advanced by 1/3 of an hour, which is 1/36 of a full circle, or 10°.
Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is: minute_deg = minute * 360 / 60 = minute * 6; The hour hand will make a complete revolution every hour, so its formula is: hour_deg = hour * 360 / 12 = hour * 30; A function to find the angle would be: int angleBetweenHands(int hour, int minute) { if(hour > 12) // In case of 24 hour clock hour -= 12; int angle = hour * 30 - minute * 6; if(angle > 180) angle = 360 - angle; return(angle); }
Assuming the hour hand moves steadily for the entirety of the hour, the angle formed by the hour and minute hand would be 55 degrees.
1200
0' or 360'
At 4 o'clock, the minute hand is at the 12, and the hour hand is at the 4. Each hour mark on a clock represents 30 degrees (360 degrees divided by 12 hours). Therefore, the angle between the hour hand and the minute hand at 4 o'clock is 4 x 30 = 120 degrees.
Say you start at 12 o'clock. If the minute hand goes around the clock once in a complete circle, it turns to 1 o'clock. thus, the hour hand makes it a 30 degree angle.