To express 90 as a product of its prime factors in ascending order, we first find its prime factorization. The prime factors of 90 are 2, 3, and 5. Therefore, 90 can be expressed as ( 2^1 \times 3^2 \times 5^1 ). In ascending order, the prime factorization is ( 2 \times 3^2 \times 5 ).
1,2,4,5,8,10,20,40
1, 2, 5, 10
1 2 4 5 10 20.
No, it can be sorted either in ascending or descending order.
2 | 2505 | 1255 | 255 | 51 | 1250 = 2 × 5 × 5 × 5
The prime factorization of 192 can be expressed as the product of its prime factors in ascending order: ( 192 = 2^6 \times 3^1 ). This means that 192 can be broken down into six 2s and one 3.
2 7
The factors of two in ascending order are 1, 2.
The factors of 32 in ascending order are: 1, 2, 4, 8, 16, 32.
Common factors of 12 and 16 in ascending order: 1, 2 & 4.
1,2,3,4,6,12
1,2,4,5,8,10,20,40
1,2,3,4,6,and 12 are the factors of 12 in ascending order.
1,2,4,8,12,18,48
2^6 x 3
1,2,3,5 are the prime factors in ascending order
1,2,4,7,14,28