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How many feet of depth is 2 atmospheres?
Two atmospheres is 67.8 feet of water.
How can you graph projectile motion?
Y axis equals altitude and X axis is distance.
What is the relationship between the altitude of an equilateral triangle and its side?
Side=x, Altitude= a (x/2)2+(x/2)2= Sqrt(a)2
How do you find the altitude of the hypotenuse in a right triangle?
By using Pythagoras' theorem: hypotenuse^2 minus base^2 = altitude^2
What is the length of the altitude of an equilateral triangle with sides of length 6?
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2
What are atmospheres distinguished by?
Altitude
What instrument is used to measure atmospheres pressure?
A barometer is used to measure atmospheric pressure. It can also measure altitude!
How many feet of depth is 2 atmospheres?
Two atmospheres is 67.8 feet of water.
High pressure equals high altitude equals warm air?
Exactly!
How many atmospheres does Venus have?
Venus has an atmospheric pressure equivalent to about 92 times that of Earth's, which is roughly 92 atmospheres.
How may feet below sea level is 2 atmospheres?
-2
How do you calculate the altitude of a triangle?
Let the given area is 10cm. Base of the triangle is 4 cm. altitude of triangle=? Area= 1/2 x Base x altitude 10= 1/2 x 4x altitude 10=2 x altitude 10/2= altitude 5= altitude Hence, altitude of the triangle is 5 cm.
What is two atmospheres?
Two atmospheres is the pressure on a diver 10.3 metres underwater.
2.75 miles altitude equals what in meters?
2.75 miles is ~4,425.7 meters.
How can you graph projectile motion?
Y axis equals altitude and X axis is distance.
What is the relationship between the altitude of an equilateral triangle and its side?
Side=x, Altitude= a (x/2)2+(x/2)2= Sqrt(a)2
How do you find the altitude of the hypotenuse in a right triangle?
By using Pythagoras' theorem: hypotenuse^2 minus base^2 = altitude^2
