acute
The sine of a complementary angle can be found using the relationship that the sine of an angle is equal to the cosine of its complement. Since the complementary angle of 28 degrees is 62 degrees (90 - 28 = 62), the sine of 62 degrees is equal to the cosine of 28 degrees. Therefore, (\sin(62^\circ) = \cos(28^\circ)).
90 - 28 = 62 degrees
It is 62 degrees because 62+28 = 90 degrees
It is 90-28 = 62 degrees
The third angle is 93 degrees
An angle of 28 degrees is an acute angle because it is greater than 0 but less than 90 degrees
90 - 28 = 62 degrees
It is 62 degrees because 62+28 = 90 degrees
Well, well, well, aren't we feeling all mathematical today? If one angle is 28 degrees in a right triangle, the other acute angle must be 62 degrees (90 - 28 = 62). As for the right angle, it's a whopping 90 degrees. Math can be a real trip sometimes, can't it?
It is 90-28 = 62 degrees
Suppose the larger angle is x degrees. Then the smaller angle is x - 2 degrees, and so they sum to 2x - 28 degrees. The two angles are complementary, so 2x - 28 = 90 is 2x = 90 + 28 = 118 so that x = 118/2 = 59 degrees and then x - 29 = 59 - 28 = 31 degrees. The two angles are 59 and 31 degrees.
90 - 28 = 62 degrees.
The third angle is 93 degrees
The difference between 90 degrees and an angle is its complement. 90 - 62 = 28 degrees.
124 degrees
the answer is 68 degrees
It is 28 degrees