Most of them start with one of those letters.
-1
If the discriminant is greater than zero (b^2 - 4ac) > 0, then the equation have two roots that are real and unequal. Further, the roots are rational if and only if (b^2 - 4ac) is a perfect square, otherwise the roots are irrational.Example:Find the equation whose roots are x = u/v and x = v/uSolution:x = u/vx - u/v = 0x = v/ux - v/u = 0Therefore:(x - u/v)(x - v/u) = (0)(0) or(x - u/v)(x - v/u) = 0Let c = u/v and d = v/u. We can write this equation in equation in the form of:(x - c)(x - d) = 0x^2 - cx - dx + CD = 0 orx^2 - (c +d)x + CD = 0The sum of the roots is:c + d = u/v + v/u = (u)(u)/(v)(u) + (v)(v)/(u)(v) = u^2/uv + v^2/uv = (u^2 + v^2)/uvThe product of the roots is:(c)(d) = (u/v)(v/u) = uv/vu = uv/uv = 1Substitute the sum and the product of the roots into the formula, and we'll have:x^2 - (c +d)x + CD = 0x^2 - [(u^2 + v^2)/uv]x + 1 = 0 Multiply both sides of the equation by uv(uv)[x^2 - ((u^2 + v^2)/uv))x + 1] = (uv)(0)(uv)x^2 - (u^2 + v^2)x + uv = 0 which is the equatiopn whose roots are u/v, v/u
1/f = 1/u+1/v Subtract 1/v from both sides: 1/f-1/v = 1/u Multiply all terms by fv: fv/f - fv/v = fv/u => v-f = fv/u Multiply all terms by u: u(v-f) = fv Divide both sides by v-f which will then make u the subject of the formula: u = fv/v-f
W t y u i o a h x v n m
U i d n v s h e
yaks (big snow cow-like animals)
There are no Australian animals starting with the letters U, V, Z or I
what is the animal that have these letters a d e e r u v n t
U Ulysses Butterfly V Vulture
V.There are no Australian animals that start with the letter V
· Vulture
P-U-N-K-S- - 1999 V is rated/received certificates of: USA:PG
narwhalnewtnightinggalenudibranchvangavaquitavicunaviperviscachavolevulture
n e v e r r u n o u t
U- ulta beauty store. E - ethinic is a store chain in New York. N- New york & Company, clothing and jewerly store. V- don't know any. Y- Yankee candle candle store.
Goof Troop - 1992 O R-V I N-V U 1-8 was released on: USA: 14 September 1992