Q: What are 25 c in a Q?

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25 cents in a quarter

The letter o, Q, Q,m, b, c, C, u,U, and there might be more.

Q = C VC = Q / V = (60/12) = 5 farads (a capacitor the size of a house)

C = 25 + (10 x 4) = 25 + 40 = 65

In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.

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25 cents in a quarter

The heat required to heat a substance is given by the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (50°C - 25°C = 25°C). Plugging in the values and rearranging for mass, we get: m = Q / (cΔT) = 2825 J / (4.18 J/g°C * 25°C) = 26.98 grams. So, the mass of water that can be heated from 25⁰C to 50⁰C by the addition of 2825 J of heat is approximately 27 grams.

q=(275)(11)(1.00) q=3,025 cal remember that the formula to find heat is: q=m(DT)Cp and remember that the specific heat of water is: 1.00 cal/(gxC) you just replace values hope this helps:)

The specific heat capacity of gold is about 0.129 J/g°C. To find the heat required to raise the temperature of 0.10 kg of gold by 25°C, you can use the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you get Q = (0.10 kg) × (0.129 J/g°C) × 25°C.

To calculate the heat lost by a substance, we use the formula: Q = mcΔT, where Q is the heat lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature. Given that the specific heat capacity of iron is 0.45 J/g°C, the heat lost by 30.0g of iron going from 56.7°C to 25°C would be: Q = 30.0g * 0.45 J/g°C * (25°C - 56.7°C). Calculate Q using this formula.

The specific heat capacity of aluminum is 900 J/kg°C. To calculate the heat required, use the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Therefore, Q = 0.10 kg * 900 J/kg°C * 25 °C = 2250 J.

The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.

The specific heat capacity of copper is 0.385 J/g°C. To calculate the heat required, you'd use the formula Q = mcΔT, where Q is the heat, m is the mass of the copper (350g), c is the specific heat capacity of copper, and ΔT is the temperature change (25°C). Plugging in the values, you'd get: Q = 350g * 0.385 J/g°C * 25°C = 3375 J.

Q= Quarter note, H= Half note, FL= Full note, |= end of bar 4 E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | F-Q F-Q F-Q F-Q | F-Q E-Q E-H 4------------------------------------------------------------------------------------------------------- E-Q D-Q D-Q E-Q | D-H G-H | E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | -------------------------------------------------------------------------------------------------------- F-Q F-Q F-Q F-Q | F-Q E-Q E-H | G-Q G-Q F-Q D-Q | C-FL |

I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c

two quavers in a crotchet

The specific heat capacity of aluminum is 0.897 J/g°C. The heat required can be calculated using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Plugging in the values, we get Q = 30.0 g * 0.897 J/g°C * (75°C - 25°C). Solving this gives Q = 1014.75 J, or approximately 1015 J.