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What are 25 c in a Q?

Updated: 9/17/2023
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14y ago

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I think this has to do with Canadian or American currency, 25 Cents in a Quarter.

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14y ago
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Q: What are 25 c in a Q?
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What does 25 equals c in a q?

25 cents in a quarter


What mass of water can be heated from 25⁰C to 50⁰C by the addition of 2825 J?

The heat required to heat a substance is given by the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (50°C - 25°C = 25°C). Plugging in the values and rearranging for mass, we get: m = Q / (cΔT) = 2825 J / (4.18 J/g°C * 25°C) = 26.98 grams. So, the mass of water that can be heated from 25⁰C to 50⁰C by the addition of 2825 J of heat is approximately 27 grams.


How much heat is required to warm 25 g of water from 20deg cto 32deg c?

q=(275)(11)(1.00) q=3,025 cal remember that the formula to find heat is: q=m(DT)Cp and remember that the specific heat of water is: 1.00 cal/(gxC) you just replace values hope this helps:)


How was heat does it take to raise the temperature of 0.10 kg of gold by 25 Celsius?

The specific heat capacity of gold is about 0.129 J/g°C. To find the heat required to raise the temperature of 0.10 kg of gold by 25°C, you can use the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you get Q = (0.10 kg) × (0.129 J/g°C) × 25°C.


How much heat lost by a 30.0g of iron with temperature from 56.7C to 25C?

To calculate the heat lost by a substance, we use the formula: Q = mcΔT, where Q is the heat lost, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature. Given that the specific heat capacity of iron is 0.45 J/g°C, the heat lost by 30.0g of iron going from 56.7°C to 25°C would be: Q = 30.0g * 0.45 J/g°C * (25°C - 56.7°C). Calculate Q using this formula.


How much heat does it take to raise the temperature of 0.10 kg of aluminum by 25 oC?

The specific heat capacity of aluminum is 900 J/kg°C. To calculate the heat required, use the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Therefore, Q = 0.10 kg * 900 J/kg°C * 25 °C = 2250 J.


How much heat energy will be required to raise the temperature of 15 grams of water 25 degrees c?

The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate the heat energy as follows: Q = 15g * 4.18 J/g°C * 25°C = 1567.5 J. Therefore, 1567.5 Joules of heat energy will be required to raise the temperature of 15 grams of water by 25 degrees Celsius.


What amount of heat is required to raise the temperature of 350 grams of copper to cause a 25C change?

The specific heat capacity of copper is 0.385 J/g°C. To calculate the heat required, you'd use the formula Q = mcΔT, where Q is the heat, m is the mass of the copper (350g), c is the specific heat capacity of copper, and ΔT is the temperature change (25°C). Plugging in the values, you'd get: Q = 350g * 0.385 J/g°C * 25°C = 3375 J.


What are the notes for jingle bell for alt sax?

Q= Quarter note, H= Half note, FL= Full note, |= end of bar 4 E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | F-Q F-Q F-Q F-Q | F-Q E-Q E-H 4------------------------------------------------------------------------------------------------------- E-Q D-Q D-Q E-Q | D-H G-H | E-Q E-Q E-H | E-Q E-Q E-H | E-Q G-Q C-Q D-Q | E-FL | -------------------------------------------------------------------------------------------------------- F-Q F-Q F-Q F-Q | F-Q E-Q E-H | G-Q G-Q F-Q D-Q | C-FL |


Q squared plus 20 q plus c?

I'm not exactly sure what you mean by this, but if you'd like to know how to do this in C here: q ^ 2 + 20 q + c


There are two Q's in a C What does Q and C stand for?

two quavers in a crotchet


How many joules of energy are required to raise the temperature of 65 grams of iron from 25 degrees celsius to 95 degrees celcsius?

The specific heat capacity of iron is 0.449 J/g°C. Using the formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, we can calculate the energy required. Q = 65g * 0.449 J/g°C * (95°C - 25°C) = 1966.25 Joules.