One way is to count by 2's five times: 2, 4, 6, 8, 10
The other way is to count by 5's two times: 5, 10
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count the cubesdo length x width x heightor you can multiply the area times the hight
There are two ways of doing it I'll tell you the easiest, you have to draw your dodecagon and then pick one specific corner and draw straight lines out to each of the other corners from this point and then Count how many triangles there are and times it by 180
I count 5, not counting the different orders that they are added as different ways. Here they are. If I missed some, then somebody else can add to it:3 + 3 + 3 + 3 + 1 = 133 + 3 + 5 + 1 + 1 = 135 + 5 + 1 + 1 + 17 + 3 + 1 + 1 + 19 + 1 + 1 + 1 + 1If you want to count different orders as unique, For #1, there are 4 additional ways (I wouldn't say that the different 3's are unique, so the 1 in each position).For #2, I count 13 additional ways. For # 3, I count 8 additional. For #4, I count 7 additional ways. And for #5, I count 4 additional ways. So that would be 36 additional ways, rearranging the orders, for a total of 41 ways.
By ones By twos By fours By eights By tens By twenties By fourty (if you want to count that one)
Count the total number of ways it can turn out. Count the number of ways that are the condition you're looking for. The probability of the outcome you're looking for is is the second number divided by the first number.