This would mean that the average of the three numbers would be 189 / 3 = 63.Therefore the three numbers you are looking for are 61 + 63 + 65.
63 / 3 = 21The middle number is 21The odd numbers next to 21 are 19 and 2319 + 21 + 23 = 63
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.
The integers are -1, 1 and 3.
This would mean that the average of the three numbers would be 189 / 3 = 63.Therefore the three numbers you are looking for are 61 + 63 + 65.
The first odd positive integers are "1" and "3" which the sum is 4.
189/3 = 63 So the three odd integers are 61, 63 and 65
63 / 3 = 21The middle number is 21The odd numbers next to 21 are 19 and 2319 + 21 + 23 = 63
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
They are are 62, 63 and 64.
The sum is infinitely large.
Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.
1680
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
There is no solution. The sum of multiple even integers will always be even, and -7 is odd.
Any set of three odd integers must be odd - for example, 3 + 5 + 7 = 15. Similarly, the sum of an even number of odd integers added together will always be an even integer.