There are an infinite number of possible answers:
(1,1,1,720), (1,1,2,360), (1,1,3,240), ...
(.1,.1,.1,720000), (-1,-1,36, 20), (5/7, 7/5, 30, 24) , etc, etc.
2,5,10,360
The product of numbers is the multiplication of the numbers. 1*2*3*4*5*6= 720.
To find four numbers that multiply to 720, one possible combination is 2, 3, 4, and 30, since (2 \times 3 \times 4 \times 30 = 720). Another combination could be 2, 5, 6, and 6, since (2 \times 5 \times 6 \times 6 = 720). There are multiple sets of numbers that can yield the product of 720.
2x2=4
To find five numbers that multiply to 720, you can use the prime factorization of 720, which is (2^4 \times 3^2 \times 5). One possible set of five numbers is 1, 2, 3, 4, and 30, since (1 \times 2 \times 3 \times 4 \times 30 = 720). Other combinations are possible as well, such as 6, 6, 4, 5, and 3.
2,5,10,360
The product of numbers is the multiplication of the numbers. 1*2*3*4*5*6= 720.
To find four numbers that multiply to 720, one possible combination is 2, 3, 4, and 30, since (2 \times 3 \times 4 \times 30 = 720). Another combination could be 2, 5, 6, and 6, since (2 \times 5 \times 6 \times 6 = 720). There are multiple sets of numbers that can yield the product of 720.
720
2x2=4
The answer will depend on the signs of the numbers being multiplied.
To find five numbers that multiply to 720, you can use the prime factorization of 720, which is (2^4 \times 3^2 \times 5). One possible set of five numbers is 1, 2, 3, 4, and 30, since (1 \times 2 \times 3 \times 4 \times 30 = 720). Other combinations are possible as well, such as 6, 6, 4, 5, and 3.
There is no such number. Every number can be multiplied by 3 and every number can be multiplied by 4.
400
12x2x2x2
The two numbers can be: 4*19 = 76
Yes, the two numbers that are multiplied together are called factors. For example, in the multiplication equation (3 \times 4 = 12), both 3 and 4 are factors of 12. Factors are the numbers that, when multiplied, produce a product.