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The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
Ways = 3C3 x 7C4 x 4C2 = 1 x 35 x 6 = 210
There are 4200, in all.
4! = 4*3*2*1 = 24 ways
4! 4 * 3 * 2 = 24 ways ==========