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The number of significant digits in a number is equal to the number of non zero digits, unless the zeroes fall to the right of the decimal place and are written, in which case all numbers from the leftmost non zero to the right most digit are counted. So, 4200.0 would have five significant digits.
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All five digits in the number are significant.
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
The answer is five. All the digits are significant.