Only two: (4, 9) and (6, 6). In all other factor pairs, one of the numbers is not composite.
five pairs
1 x 36 2 x 18 3 x 12 4 x 9 6 x 6
factor pair = 36,1factor pair = 18,2factor pair = 12,3factor pair = 9,4factor pair = 6,6
The prime factorization of 36 is 2 x 2 x 3 x 3 We can see that 2, 3, 4 and 6 are factors of 36. Dividing those numbers into 36 will give you the rest of the factor pairs. (36, 1) (18, 2) (12, 3) (9, 4) (6, 6)
Assuming the 36 numbers are all different, there are 36*35/2 = 630 pairs.
The factor pairs of 36 are: 1 X 36 2 X 18 3 X 12 4 X 9 6 X 6 Those are all the factors of 36.
(36,1)(18,2)(12,3)(9,4)(6,6)
(1, 36) (2, 18) (3, 12) (4, 9) (6, 6)
(36,1)(18,2)(12,3)(9,4)(6,6)
1,36,2,18,3,12,4,9,6
1 and 36 or 2 and 36 are two possible pairs.
Single numbers don't have LCMs, much less pairs of them. Pairs of LCMs don't exist because only one number can be least. Other than that...The factor pairs of 36 are (36,1)(18,2)(12,3)(9,4)(6,6)
Only two: (4, 9) and (6, 6). In all other factor pairs, one of the numbers is not composite.
Divide 1, 2, 3, 4 and 6 into 36. The answers are the other halves of the factor pairs.
The factor pairs of 36 are:1 × 36 = 362 × 18 = 363 × 12 = 364 × 9 = 366 × 6 = 36
36 i believe