The list is infinite.
35, 70, 105 etc
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∙ 14y agoThere are infinitely many common multiples of 3, 5 and 7, each one 105 larger than the previous one. Or to put it another way: the common multiples of 3, 5 and 7 are the multiples of their lowest common multiple which is 105. ie their common multiples are all the multiples of 105, of which there is no end - there is an infinite number of multiples of 105 (or any other number [except zero]).
35,70,105.140
First, we need to fin the LCM of 2, 5, and 7, wich is 70. So that all the multiples of 70 are all common multiples of 2, 5, and 7 such that: 70 x 1 70 x 2 70 x 3 70 x 4 . . .
35..
Since all 3 are prime numbers LCM = 3 * 5 * 7 = 105 All multiples of 105 are multiples of 3, 5 and 7
There are infinitely many common multiples of 3, 5 and 7, each one 105 larger than the previous one. Or to put it another way: the common multiples of 3, 5 and 7 are the multiples of their lowest common multiple which is 105. ie their common multiples are all the multiples of 105, of which there is no end - there is an infinite number of multiples of 105 (or any other number [except zero]).
Common multiples of 7 and 5 include 35, 70, 140, etc.
There is an infinite number of common multiples for these numbers!
35 and 70 both have 7 and 5 as prime factors
Since 14 is a multiple of 7, all of its multiples are common.
35,70,105.140
First, we need to fin the LCM of 2, 5, and 7, wich is 70. So that all the multiples of 70 are all common multiples of 2, 5, and 7 such that: 70 x 1 70 x 2 70 x 3 70 x 4 . . .
35
35
35..
Since all 3 are prime numbers LCM = 3 * 5 * 7 = 105 All multiples of 105 are multiples of 3, 5 and 7
The common multiples of 3, 5, 7, 9, and 11 are the numbers that are divisible by all of these numbers. The least common multiple (LCM) of these numbers is 10395. Therefore, any multiple of 10395 is a common multiple of 3, 5, 7, 9, and 11.