Q: What are all of the factors of 252?

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As a product of its prime factors: 2*2*3*3*7 = 252

2, 3, 7,

252 Divide by two. 126,2 Divide by two. 63,2,2 Divide by three. 21,3,2,2 Divide by three. 7,3,3,2,2 Stop. All the factors are prime.

The factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126 and 252. For them to be common, they need to be compared to another set of factors.

252 = 2 x 2 x 3 x 3 x 7 or 22 x 32 x 7

Related questions

252 = 2 * 2 * 3 * 3 * 72, 3 and 7.The prime factors of 252 are: 2, 3, 7

252 is divisible by any of its factors including itself

The Prime Factors of 224 are 2, 7The Prime Factors of 252 are 2, 3, 7

The LCM of 12, 18, and 21 is 252 Factors of 12: 2^2, 3 Fadtors of 18: 2, 3^2 Factors of 21: 3, 7 Since the LCM of a set of numbers is mathematically defined to be the product of all the prime factors in the set taken to the highest degree they appear, the LCM must be the product of 22 X 32 X 7 = 252. 252 is the smallest number to be divisible by 12, 18, and 21.

Factors of 252 = 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, 252

The GCF is 36.

They are: 2*2*3*3*7 = 252

Itself and any of its factors

1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, 252

1, 2, 3 and 6 are common factors of 252 and 30.

The common factors of 252 and 4 are 1, 2 4.

As a product of its prime factors: 2*2*3*3*7 = 252