If there were two prime factors of 130, then they would have to be the only possible factors of 130.If either of them could be broken down to smaller factors, it wouldn't be a prime number.In addition to '1' and '130' ... 2, 5, 10, 13, 26, and 65 are also factors of 130. So there can't be two prime factors.
If it has no prime factors in common. The prime factors of 16 are all twos and the prime factors of 27 are all threes. 16/27 has to be in simplest form.
130
2 x 5 x 13 = 130
Factors of 27: 1, 3, 9, 27
All the factors of 130 are: 1, 2, 5, 10, 13, 26, 65, 130
130 65,2 13,5,2
The factors of 27 are: 1, 3, 9, 27.
all factors of 130 are 1, 2, 5, 10, 13, 26, 65, 130
The factors of 27 are 27, 9, 3 and 1
1, 2, 5, 10, 13, 26, 65, 130.
The factors of 27 are 1, 3, 9, and 27. The factors of 38 are 1, 2, 19, and 38.
1 and 27
The factors of 130 are 1, 2, 5, 10, 13, 26, 65, and 130.
Since 9 is a factor of 27, all of its factors are common.
1, 3, 9, 27.
They are: 1, 3, 9 and 27