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If it could be 3333, then your answer would be four to the fourth power, which is 256.

Can prove that as: The first number has 4 possibilities, and the second has 4 possibilities, so if each of the possibilities in the first number has four possibilities for the second number, the number of possibilities of the two is 16, and that can continue if the third number as four possibilities, so you can have 64 combination of those three numbers, and of those 64 numbers each of them could have 4 different numbers after them, so you have 256 combinations.

If it could not repeat digits it would be 4x3x2x1 which is 24.

can prove that as:

1.3456

2.3465

3.3546

4.3564

5.3645

6.3654

7.4356

8.4365

9.4536

10.4563

11.3635

12.4653

13.5346

14.5364

15.5436

16.5463

17.5643

18.5634

19.6345

20.6354

21.6435

22.6453

23.6534

24.6543

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15y ago

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Q: What are all of the possible 4 digit numeric combinations using 3-6?
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