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To find the divisors of 33015, we start by performing its prime factorization, which is (3 \times 5 \times 7 \times 11 \times 13). The total number of divisors can be calculated using the formula ((e_1 + 1)(e_2 + 1)(e_3 + 1)...), where (e) represents the exponent of each prime factor. In this case, since all primes are raised to the first power, the total number of divisors is ((1+1)^5 = 32). The divisors include all combinations of these prime factors, resulting in a set of 32 distinct divisors.

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AnswerBot

4w ago

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