(1,1)
(2,1)
(3,1)
(4,1)(2,2)
(5,1)
(6,1)(3,2)
(7,1)
(8,1)(4,2)
(9,1)(3,3)
(10,1)(5,2)
(11,1)
(12,1)(6,2)(4,3)
(13,1)
(14,1)(7,2)
(15,1)(5,3)
(16,1)(8,2)(4,4)
(17,1)
(18,1)(9,2)(6,3)
(19,1)
(20,1)(10,2)(5,4)
(21,1)(7,3)
(22,1)(11,2)
(23,1)
(24,1)(12,2)(8,3)(6,4)
(25,1)(5,5)
(26,1)(13,2)
(27,1)(9,3)
(28,1)(14,2)(7,4)
(29,1)
(30,1)(15,2)(10,3)(6,5)
(31,1)
(32,1)(16,2)(8,4)
(33,1)(11,3)
(34,1)(17,2)
(35,1)(7,5)
(36,1)(18,2)(12,3)(9,4)(6,6)
(37,1)
(38,1)(19,2)
(39,1)(13,3)
(40,1)(20,2)(10,4)(8,5)
(41,1)
(42,1)(21,2)(14,3)(7,6)
(43,1)
(44,1)(22,2)(11,4)
(45,1)(15,3)(9,5)
(46,1)(23,2)
(47,1)
(48,1)(24,2)(16,3)(12,4)(8,6)
(49,1)(7,7)
(50,1)(25,2)(10,5)
(51,1)(17,3)
(52,1)(26,2)(13,4)
(53,1)
(54,1)(27,2)(18,3)(9,6)
(55,1)(11,5)
(56,1)(28,2)(14,4)(8,7)
(57,1)(19,3)
(58,1)(29,2)
(59,1)
(60,1)(30,2)(20,3)(15,4)(12,5)(10,6)
20
The factor pairs of 1600 are (1600,1)(800,2)(400,4)(320,5)(200,8)(160,10)(100,16)(80,20)(64,25)(50,32) None of them add up to 332.
(6375,1)(2125,3)(1275,5)(425,15)(375,17)(255,25)(125,51)(85,75)
75
How about 2 and 12 or 4 and 10
30
20
There are really only three distinct factor pairs:(16, 1) (8, 2)(4, 4)I suppose if you count (1,16) and (2,8) as being different from (16, 1) and (8,2), you could end up with as many as five factor pairs.
The factor pairs of 1600 are (1600,1)(800,2)(400,4)(320,5)(200,8)(160,10)(100,16)(80,20)(64,25)(50,32)(40,40) None of them add up to 60.
The factor pairs of 3000 all have a product of 3000. None of them add up to -155.
The factor pairs of 1600 are (1600,1)(800,2)(400,4)(320,5)(200,8)(160,10)(100,16)(80,20)(64,25)(50,32) None of them add up to 332.
The factor pairs of 1600 are (1600,1)(800,2)(400,4)(320,5)(200,8)(160,10)(100,16)(80,20)(64,25)(50,32)(40,40) None of them add up to 60. If that was -1600, you could use 80 and -20.
The factor pairs of 36 are pairs of numbers that multiply together to equal 36. These pairs include (1, 36), (2, 18), (3, 12), (4, 9), and (6, 6). Factors are numbers that can divide evenly into a given number, and in this case, 36 has a total of 9 factor pairs.
(6375,1)(2125,3)(1275,5)(425,15)(375,17)(255,25)(125,51)(85,75)
75
How about 2 and 12 or 4 and 10
When you say "factors" there are 3 different things this could mean.Prime factors (this is probably not the one you want, but it will help later). You usually do this with a "factor tree". Pencil and paper would make it look like a tree!Find the prime factorization of 60: 60 = 6x10 = (2x3)x(2x5) = 2x2x3x5. (=22x3x5).All factors of a number (this sounds like the one you want): All the numbers from 1 to 60 inclusive which divide evenly into the number; you can find these by looking at the prime factors: 1,2,3,4,5,6,10,12,15,20,30,60.All factor pairs: what two numbers can you multiply to give 60? They are made up from the factors you just found: 1x60, 2x30, 3x20; 4x15, 5x12, 6x10.