I am assuming you are referring to a normal 3x3 sudoku grid, where you can only use the numbers 1-9 once in the grid, and by prime number you mean the 3digit number across and down the grid must be prime? For a number to be prime, it must end in 1, 3, 7 or 9. There are 5 places on the Sudoku grid for a number to finish and as you can only use a number once in sudoku you have one place left where the number can not be prime. This means the most you can have is 5 prime numbers.
All square numbers greater than 1 are composite.
There is no simple answer because there is no known pattern to prime numbers. You could try dividing the each number by all the prime numbers less than or equal to its square root. If none of the go into the number then it is a prime.
There are an infinite number of square numbers and prime numbers whose sums are a prime number. Examples are 202 + 103 = 503, 22 + 13 = 17, 102 + 601 = 701, 22 + 163 = 167, 42 + 141 = 157, etc.
It's an enormous list; we wouldn't be able to get them all. All of the prime numbers in that range are co-prime with each other. The composite numbers, as long as they aren't multiples of the primes, are co-prime with the primes. The square numbers are co-prime with each other and quite a few of the composite numbers are co-prime with each other. If you could narrow the range, we could be more specific.
it looks like a 100 square grid with 1 to 100 and you highlight all the prime numbers
None because square numbers have more than two factors
I am assuming you are referring to a normal 3x3 sudoku grid, where you can only use the numbers 1-9 once in the grid, and by prime number you mean the 3digit number across and down the grid must be prime? For a number to be prime, it must end in 1, 3, 7 or 9. There are 5 places on the Sudoku grid for a number to finish and as you can only use a number once in sudoku you have one place left where the number can not be prime. This means the most you can have is 5 prime numbers.
Prime numbers have two factors. All square numbers (other than 1) have more than that.
Work It Out By Drawing A Grid, Eliminate the 2 Times Tables, Then 3, Then 5, Then 7, Then 11, Then 13, And All The Primes, And Your Be Left With The Higher Prime Numbers :D
I might be reading this incorrectly, but it seems to me that I can take two prime numbers, 3 and 3, and make the square number nine out of them. This is also true of all the other prime numbers.
All square numbers greater than 1 are composite.
All numbers that are the square of primes have exactly 3 factors.
There is no simple answer because there is no known pattern to prime numbers. You could try dividing the each number by all the prime numbers less than or equal to its square root. If none of the go into the number then it is a prime.
No. 19 is a prime number, and all prime numbers have irrational roots.
There are an infinite number of square numbers and prime numbers whose sums are a prime number. Examples are 202 + 103 = 503, 22 + 13 = 17, 102 + 601 = 701, 22 + 163 = 167, 42 + 141 = 157, etc.
Every square number (except 1) is composite. Prime numbers only have two factors, one and the numbers themselves. Since square numbers also have at least the square roots as factors, they have to be composite.