8X36
That would be 3 x 9 inches.
Area is length times width, perimeter is twice the sum of length and breadth.
length times width
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
18.4cm by 22.4cm
To find the dimensions of the rectangle, we need to set up equations based on the given area and perimeter. The area of a rectangle is length multiplied by width, so length times width equals 12 cm. The perimeter of a rectangle is given by the formula 2(length + width), which in this case equals 16 cm. By solving these two equations simultaneously, we can find the dimensions of the rectangle.
That would be 3 x 9 inches.
2 times (length + width)
Area is length times width, perimeter is twice the sum of length and breadth.
the length is equal to 160,083
The area is the length times the width. The perimeter is two times the length plus two times the width.
length times width
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).
The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.