2,5,13,647,809
To form a five-digit number using the digits 1, 2, 3, 4, and 5, each digit must be used exactly once. Since there are 5 unique digits, the total number of different five-digit numbers that can be formed is given by the factorial of the number of digits, which is 5! = 120. Therefore, 120 different five-digit numbers can be formed using the digits 12345.
Using each one only once, 5*4*3*2*1 = 120 of them.
3! = 6.
only using the numbers once
None.
There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
61
To form a five-digit number using the digits 1, 2, 3, 4, and 5, each digit must be used exactly once. Since there are 5 unique digits, the total number of different five-digit numbers that can be formed is given by the factorial of the number of digits, which is 5! = 120. Therefore, 120 different five-digit numbers can be formed using the digits 12345.
9
3
Using each one only once, 5*4*3*2*1 = 120 of them.
I'm not sure what you're asking. The smallest number that can't be between two primes is obviously 1. Once you start running into primes, every composite number is between at least two primes.
3! = 6.
only using the numbers once
5*4+3+2
21 and three left over
24 this is a factorial if you come across a question like this again count how many then multiply down from that number. 4x3x2x1 for four 5x4x3x2x1 for five and so on