The least common multiple of all of these numbers is 360. This is the smallest number that is divisible by all five numbers. Any whole number multiple of 360 will also be divisible by all five numbers, so:
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All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
No. Consider 6 and 10.
A number that is divisible by 2, 3, 4, 5, 6, 8, 9, and 10 must be divisible by the least common multiple (LCM) of these numbers. The LCM of 2, 3, 4, 5, 6, 8, 9, and 10 is 360. Therefore, any multiple of 360 will be divisible by all of these numbers.
It is not evenly divisible by any of the numbers you've mentioned.