Rearrange the first equation: x=8-2y. Plug in this value of x into the second equation: 2(8-2y)+y=7. Simplify: 16-4y+y=7. -3y=-9. y=3. Plug this value of y into the first equation: x+2(3)=8. Solve for x: x=8-6. x=2. The answer is {2,3)
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the answer is - (not are) : (-1, 3).
(5,3)
The answer is - not are - (-6, 9).
Solving the simultaneous equations: x = -237/11 and y = 90/11
2x plus 3y
(x, y) = (3, 2)
(0,4) and (-2, 0)
There are an infinite number of ordered pairs. (-5, -7) is one pair
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
k
The ordered pair is (1, 3).
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the answer is - (not are) : (-1, 3).
(5,3)
The answer is - not are - (-6, 9).
There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.
Solving the simultaneous equations: x = -237/11 and y = 90/11