-2x-6= -2x-6Another answer:-2x-6 = 2x+6-2x-2x = 6+6-4x = 12x = -3
2x - 3 = 2x - 52x = 2x - 22x - 2x = -20 =/= -2Zero is not equal to -2 so the answer is no solution.
d/dx sec(2x) = 2sec(2x)tan(2x)
8x4
60-2x = 70-4x 60-2x+2x = 70-4x+2x 60 = 70 +2x 60-70 = 70 + 2x - 70 -10 = 2x x = -10/2 = -5
Hopefully I did this one correctly, if anyone sees an error please correct it. This is the problem:∫(2x+7)/(x2+2x+5)I rewrote the integral as:2∫x/(x2+2x+5) + 7∫1/(x2+2x+5)Both of these parts of the integral is in a form that should be listed in most integral tables in a calculus text book or on-line. From these tables the integral is the following:2*[(1/2)ln|x2+2x+5| - (1/2)tan-1((2x+2)/4)] + 7*[(1/2)tan-1((2x+2)/4)]Combining like terms gives the following:ln|x2+2x+5| + (5/2)*tan-1((2x+2)/4)
Because we use a base 10 numbering system, and 2 and 5 are the factors of 10.
yes because it is in the 5x 2x 10x and 1x tables xx abbey
It is 2x+(-2x) = 0
2X * 2X * 2X = 8X^3 2X^3 is saying 2*( X * X * X) = 2X^3
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
-2x-6= -2x-6Another answer:-2x-6 = 2x+6-2x-2x = 6+6-4x = 12x = -3
6x
2x2 + 2x = 2x(x+1)
2x+x is 3x
2x-4y=-8-2x......-2x-4y=-2x-8(-4y)/-4 | (-2x-8)/-4y=1/2x+2
10x 2x divide 2x equals?