There are infinitely many sums, not just 3:
0 + 57
0.5 + 56.5
0.005 + 56.995
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
3 multiplied by 57 is 171.
To find how many times 3 fits into 57, you can divide 57 by 3. Doing the calculation, 57 ÷ 3 equals 19. Therefore, there are 19 threes in 57.
19
Yes: 3 x 19 = 57
A single number can have only one sum: in this case, 57.
What is sums? Is it sims 3
There are infinitely many answers. How about 2 + sqrt(37) and 55 - sqrt(37). Add them together and what have you got? 57 So, as you can see, there are lots and lots of possible answers.
57/3
The sums are: 1: 15 2: 34 3: 42
Yes, 3 is a factor of 57. 3 x 19 = 57.
57 + 3 = 60
The factors of 57 are: 1, 3, 19, 57
57/3 = 19 19*3=57
The GCF of 27 and 57 is 3
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
Well, 1 is equal to 1. 9 is equal to 9. So any number from 0 to 9. I do not think this is what is meant by the question. If you mean any number with more than one digit. There is no such number. Because 11 sums to 2. 19 sums to 10. 21 sums to 3. 29 sums to 11. 111 sums 3. 119 sums to 11. The sums do not grow as fast the increase of digits.