25 square meters
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
The area of rectangle is : 100.0
Assuming that your square has equilateral sides, it would be 25 sq inches. Area = Heigth x Width Remember, a square is a rectangle, but a rectangle is not a square.
The area of the rectangle is the length of the perpendicular sides (ie the sides which meet at right angles) multiplied together.This could be solved by using Pythagoras to find the lengths of the two sides between the given points, but a quick inspection shows that the rectangle is aligned orthogonally (ie parallel to the x- and y-axes) and so only the difference between the corresponding x- and y- coordinates need be calculated before multiplying together.The side between (1, 9) and (6, 9) has a length of (6 - 1) = 5 unitsThe side between (6, 4) and (6, 9) has a length of (9 - 4) = 5 units→ area of the rectangle = 5 units × 5 units = 25 square units. Note: as the perpendicular sides are equal, all four sides are equal in length and this is the special rectangle which is called a square.
25 square meters
15 and 20 inches because these dimensions comply with Pythagoras' theorem and the area of the rectangle.
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
The rectangle is in fact a square with 4 equal sides of 5 units in length.
Then the square will have 4 equal sides of 5cm with a perimeter of 20cm and an area of 25 square cm
The area of rectangle is : 100.0
Assuming that your square has equilateral sides, it would be 25 sq inches. Area = Heigth x Width Remember, a square is a rectangle, but a rectangle is not a square.
The greatest area is attained when the rectangle is, in fact, a square. Then it has sides of 5 cm and an area of 25 cm2. If you are not permitted to have a square then the answer is as close to 25 cm2 as you can get without actually getting there. So, more than 24.99, more than 24.99999 etc but never quite 25.
The area of the rectangle is the length of the perpendicular sides (ie the sides which meet at right angles) multiplied together.This could be solved by using Pythagoras to find the lengths of the two sides between the given points, but a quick inspection shows that the rectangle is aligned orthogonally (ie parallel to the x- and y-axes) and so only the difference between the corresponding x- and y- coordinates need be calculated before multiplying together.The side between (1, 9) and (6, 9) has a length of (6 - 1) = 5 unitsThe side between (6, 4) and (6, 9) has a length of (9 - 4) = 5 units→ area of the rectangle = 5 units × 5 units = 25 square units. Note: as the perpendicular sides are equal, all four sides are equal in length and this is the special rectangle which is called a square.
Assuming the numbers are in metres! 25 × 9 = 225 square metres.
A = L x W5 x 5 = 25 cm²
Well, honey, you just divide the area by the side length to find the other side length. So, 1125 divided by 25 gives you 45. Then you draw a rectangle with sides of 25 units and 45 units using the grid as a guide. Voila, you've got yourself a rectangle with an area of 1125 square units!