6, 12 and 18.
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The way to solve this is as follows:Find the least common multiple of the two numbers.Multiply this least common multiple by 2 and by 3, to get the next two common multiples.
it is 109
There is no largest common multiple of any set of numbers as whatever value is assumed to be the largest can be increased by adding the lowest common multiple of the numbers to get an even larger common multiple. For 2 and 3 the lowest common multiple is 6. So whatever number is assumed to be the largest common multiple it can always be increased by 6 to get a larger common multiple.
I believe that would be 18. 18 is evenly divisible by all three of those numbers.
They are: 30, 60 and 90