LXV
65
It is: 65 = LXV
LXV = 50+10+5
L=50, X=10 and V=5. So LXV=65.
Presumably you mean 4.7.65 in which case the answer is IV.VII.LXV
65
It is: 65 = LXV
LXV
LXV = 50+10+5
L=50, X=10 and V=5. So LXV=65.
The Roman numerals for 64 are ILXV (65-1) or LXIIII (64) and they are not LXIV. So your question is: What is the cube root of LXIIII in Arabic numerals? The answer is 4 which is IIII or IV in Roman numerals.
Presumably you mean 4.7.65 in which case the answer is IV.VII.LXV
The number is 65. L = 50 X = 10 V = 5
Arabic(Modern) = 11 Roman = XI Here are the first 20 Roman Numerals 1 = I 2 = II 3 = III 4 = IV ( or IIII on classic dials of clocks). 5 = V 6 = VI 7 = VII 8 = VIII 9 = IX 10 = X 11 = XI 12 = XII 13 = XIII 14 = XIV 15 = XV 16 = XVI 17 = XVII 18 = XVIII 19 = XIX 20 = XX NB The first ;12; numbers you will find on analogue clocks with a classic dial.
Roman numerals were inspired by Etruscan numerals of which Roman numerals originated from.
LXV represents the number 65 in Roman numerals. It is formed by combining the symbols L (50), X (10), and V (5), which together sum to 65. Roman numerals are a numeral system originating from ancient Rome, using combinations of letters from the Latin alphabet.
In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.In Roman numerals 522 would be DXXII.