There is no simple formula to calculate probabilities for the normal distribution. Those for the standard normal have been calculated by numerical methods and then tabulated. As a result, probabilities for the standard normal can be looked up easily.
The standard normal distribution is tabulated. The critical values for various outcomes can therefore be worked out easily from tables. The normal distribution is extremely difficult to integrate: most people, even with a university degree in mathematics will be unable to do so. So working out the probability of events from the normal distribution is near enough impossible.
You do not solve a standard normal distribution. It is not a question nor an equation or inequality to be solved. You can answer questions using the standard normal distribution but what you do depends on the question and on what information is given.
One advantage of using normal distribution is that there are less errors. A disadvantage of normal distribution is that it can not be interpreted to terms of probabilities.
One advantage of using normal distribution is that there are less errors. A disadvantage of normal distribution is that it can not be interpreted to terms of probabilities.
Yes. Normal (or Gaussian) distribution are parametric distributions and they are defined by two parameters: the mean and the variance (square of standard deviation). Each pair of these parameters gives rise to a different normal distribution. However, they can all be "re-parametrised" to the standard normal distribution using z-transformations. The standard normal distribution has mean 0 and variance 1.
The standard normal distribution is tabulated. The critical values for various outcomes can therefore be worked out easily from tables. The normal distribution is extremely difficult to integrate: most people, even with a university degree in mathematics will be unable to do so. So working out the probability of events from the normal distribution is near enough impossible.
You do not solve a standard normal distribution. It is not a question nor an equation or inequality to be solved. You can answer questions using the standard normal distribution but what you do depends on the question and on what information is given.
One advantage of using normal distribution is that there are less errors. A disadvantage of normal distribution is that it can not be interpreted to terms of probabilities.
One advantage of using normal distribution is that there are less errors. A disadvantage of normal distribution is that it can not be interpreted to terms of probabilities.
You may transform a normal distribution curve, with, f(x), distributed normally, with mean mu, and standard deviation s, into a standard normal distribution f(z), with mu=0 and s=1, using this transform: z = (x- mu)/s
Yes. Normal (or Gaussian) distribution are parametric distributions and they are defined by two parameters: the mean and the variance (square of standard deviation). Each pair of these parameters gives rise to a different normal distribution. However, they can all be "re-parametrised" to the standard normal distribution using z-transformations. The standard normal distribution has mean 0 and variance 1.
0.0375
p(Z<0.35) - 0.5 = 0.6900
The normal distribution allows you to measure the distribution of a set of data points. It helps to determine the average (mean) of the data and how spread out the data is (standard deviation). By using the normal distribution, you can make predictions about the likelihood of certain values occurring within the data set.
The standard deviation stretch is used to stretch the output values using a normal distribution. The result of this stretch is similar to what is seen by the human eye.
It is necessary to use a continuity correction when using a normal distribution to approximate a binomial distribution because the normal distribution contains real observations, while the binomial distribution contains integer observations.
Yes, if you mean normal with a mean other than 0 and/or standard error other than 1. If m is the mean and s the standard error, then transform the original data, y, using: z = (y - m)/s z will have the N(0,1) distribution!!!!!!!