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What is the probability of pulling 7 spades in a row from a deck of 52 cards?
The answer is 8,648,640 in 674,274,182,400 or approximately 0.128%. To pull seven spades in a row from a deck of 52 cards may be translated as follows: In a deck of 52 cards there are 13 spades, so 13 chances to pull a spade or 13/52. After pulling one spade, there are 12 spades left and 51 cards left, so 12 chances to pull a spade or 12 / 51. After pulling the second spade, there are 11 spades left and 50 cards left, so 11 chances to pull a spade or 11 / 50. Continuing the above logic to the natural conclusion, we get the following multipliers: 13 / 52 * 12 / 51 * 11 / 50 * 10 / 49 * 9 / 48 * 8 / 47 * 7 / 46 which is equal to 8,648,640 / 674,274,182,400 or approximately 0.128%.
When pulling out 10 cards from a standard deck of 52 what are the chances of pulling at least one ace?
Prob(At least one ace in ten cards out of 52) = 1 - Prob(No aces in ten cards out of 52) When you start there are 48 non-ace cards out of 52, At the next draw, there are 47 non-ace cards out of 51, and so on = 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
How many ace of spade are in a deck of 52 cards?
1
What is the probability of picking a spade from a pack of 52 playing cards?
13/52 = .25
What is the probability from drawing 4 spades from a deck of cards?
In an ordinary deck of cards, there are 52 cards out of which 13 are spades. This means that the chances of drawing the first spade is 13 out of 52. The probability of the second spade is 12 out of 51 because one spade and, incidentally, one card are now missing. The third spade comes out as 11 out of 50 and the last one as 10 out of 49. Total probability of events that don't affect each other is the product of the individual probabilities. Thus, the chances of drawing four spades is (13 / 52) * (12 / 51) * (11 / 50) * (10 / 49), which is about 0.00264 -- in other words, one to 379.
