The coords are (6, 1).
The distance is 6.4 units.
To evaluate (5a + 5b) where (a = -6) and (b = -5), substitute the values into the expression: [ 5(-6) + 5(-5) = -30 - 25 = -55. ] Therefore, (5a + 5b = -55).
25 x 6 = 150 25 x -6 = -150
The distance is 6.4 units.
To evaluate (5a + 5b) where (a = -6) and (b = -5), substitute the values into the expression: [ 5(-6) + 5(-5) = -30 - 25 = -55. ] Therefore, (5a + 5b = -55).