Sides must add to 50 and multiply to 600; 20 & 30 fit. Length is 30 cm, width is 20 cm.
You forgot to put in the length of the rectangle's perimeter.
The dimensions of the rectangle are 5 cm by 4 cm
I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm
The dimensions are: 3.5 cm and 4.5 cm Check: perimeter = 3.5+4.5+3.5+4.5 = 16 cm and area = 3.5*4.5 = 15.75 cm2
Sides must add to 50 and multiply to 600; 20 & 30 fit. Length is 30 cm, width is 20 cm.
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
Try a rectangle with dimensions of 6 cm and 7 cm, and see what you get.
You forgot to put in the length of the rectangle's perimeter.
The dimensions of the rectangle are 5 cm by 4 cm
I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm
4cm x 5cm
7.5cm x 4.5cm
The dimensions are: length 10.5 cm and width 3.5 cm Check: 2*(10.5+3.5) = 28 cm
Yes if its dimensions were 3 cm and 12 cm.
The dimensions are: 3.5 cm and 4.5 cm Check: perimeter = 3.5+4.5+3.5+4.5 = 16 cm and area = 3.5*4.5 = 15.75 cm2
4cm by 13cm