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What are the dimensions of a right angle triangle whose shortest side is 10.2 cm and has an area of 69.36 square cm?
Wiki User
∙ 13y ago
Let the base be 10.2 and the height be x:-
0.5*10.2*x = 69.36
Multiply both sides by 2 and then divde both sides by 10.2 to find the value of x:-
x = 13.6 cm
Use Pythagoras' theorem to find the hypotenuse of the triangle:-
10.22+13.62 = 289 and the square root of this is 17
So the dimensions are: hypotenuse 17 cm, height 13.6 cm and base 10.2 cm
Wiki User
∙ 13y ago
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