If the last two digits of a number are divisible by 4, the whole number is divisible by 4.
If the sum total of the digits in a number are a multiple of 9, the whole number is a multiple of 9.
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The last two digits (the tens and units) are divisible by 4.This is equivalent to the following two conditions:If the tens digit is even, the units digit must be 0, 4 or 8If the tens digit is odd, the units digit must be 2 or 6For divisibility by 9, calculate the digital root: this is the sum of all the digits in the number. Repeat with the digits of this number - and keep repeating until you are down to a single digit. It that is 9, then the number is divisible by 9 and if not, it is not.
You have to use the rules of 4 and 9 Using the rules of 2 and 18 won't work because the smallest common multiple of 2 and 18 is 18 not 36. 3 and 12 won't work either because the smallest common multiple of 3 and 12 is 12 not 36. However 4 and 9 does work because their biggest common divisor is 1 so multiplying them works. The biggest common divisor of 2 and 18 is 2 and the biggest common divisor of 3 and 12 is 3
$5. Most rounding rules say to round 0 to 4 down, and 5 to 9 up.
-9
-9 - (-5) = -4 You know like you do: -10 - 9 is the same as -10 + -9 that seems easier ^^ The same rules apply to -9 - -5. When you change the subtraction sign to a plus, you have to make the negative five a positive.