It is not possible to answer the question without the numerical value of Y.
Yes.
(144 - y2) = (12 + y) (12 - y)
30+6(21^0.5) ~ 57.49545 30-6(21^0.5) ~ 2.50455 X*Y=144 X=144/Y X+Y=60 X=60-Y 144/y = 60 - Y 144 = 60Y - Y^2 Y^2-60Y+144=0 Quadratic equation gives you: 30+6(21^0.5) ~57.49545 30-6(21^0.5) ~2.50455
151
It is not possible to answer the question without the numerical value of Y.
-168
1, 2, 4, 8, 16, x, y 2 is prime.
5 times 7 times x times y = 35xy 5 and 7 are prime numbers.
Yes.
(144 - y2) = (12 + y) (12 - y)
First you express the numbers as their prime factors: 3y = 3, y y2 = y, y Next you identify any common prime factors. In this case both numbers have y as a prime factor. Finally you multiply the numbers and divide by the HCF: 3y(y2)/y = 3y2 and thus the LCM is 3y2
30+6(21^0.5) ~ 57.49545 30-6(21^0.5) ~ 2.50455 X*Y=144 X=144/Y X+Y=60 X=60-Y 144/y = 60 - Y 144 = 60Y - Y^2 Y^2-60Y+144=0 Quadratic equation gives you: 30+6(21^0.5) ~57.49545 30-6(21^0.5) ~2.50455
That depends on the value of y but 40 as a product of its prime factors is 2*2*2*5 or as 23*5
"144" in Spanish is "ciento cuarenta y cuatro".
There are no factors of 200, prime or otherwise, that are larger than 200.
The numbers that multiply to 144 and equal 7 are not whole numbers. To find these numbers, we need to use algebra. Let the two numbers be x and y. We can set up the equation xy = 144 and x = 7/y. Substituting the second equation into the first gives us y(7/y) = 144, which simplifies to 7 = 144/y. Solving for y, we get y = 144/7, which is approximately 20.57. Therefore, the numbers that multiply to 144 and equal 7 are approximately 7 and 20.57.