3, 5 and 7 have 2 factors. 81, 625 and 2401 have 5 factors.
Factors of 90: 2*3^2*5 Factors of 100: 2^2*5^2
The prime factorization of 1800 is 2 * 2 * 2 * 3 * 3 * 5 * 5, so the prime factors of 1800 are 2, 3 and 5
Its prime factors are 2, 3, 5 and as a product of its prime factors in exponents 2^3 times 3^3 times 5^3 = 27,000
As a product of its prime factors: 2*2*3*5 = 60
The prime factors of 2, 3 and 5 are 2, 3 and 5 respectively.
3, 5 and 7 have 2 factors. 81, 625 and 2401 have 5 factors.
As a product of its prime factors: 2*2*2*3*3*3*5*5*5 = 27,000
150 factors as 2 * 3 * 5 * 5 .
210 factors to [2 3 5 7] 360 factors to [2 2 2 3 3 5] Common factors are [2 3 5] Answer is 30.■
The factors of 3 are: 1, 3 The factors of 5 are: 1, 5 The factors of 10 are: 1, 2, 5, 10
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, and 24.The prime factors of 24 are: 2 and 3.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
Factors: (will fill in later).Prime Factors: 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5
225=3x75=32x25=32x5x5=32x52 prime factors are 3 and 5.The proper prime factors of 225 are 3, 3, 5, 5.The proper prime factors of 225 are 3, 3, 5, 5.
The factors of 25 are: 1 5 25.The prime factors are: 5 x 5The factors of 40 are: 1 2 4 5 8 10 20 40.The prime factors are: 2 x 2 x 2 x 5
Factors of 90: 2*3^2*5 Factors of 100: 2^2*5^2
The prime factorization of 1800 is 2 * 2 * 2 * 3 * 3 * 5 * 5, so the prime factors of 1800 are 2, 3 and 5