The factors of 52 are:
1, 2, 4, 13, 26, 52
The factors of 82 are:
1, 2, 41, 82
The factors of 132 are:
1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, 132
The Least Common Multiple (LCM) for 52 132 is 1,716.
Find the prime factors of 8450. These are 2 x 52 x 132 We can then write, √ 8450 = √ (2 x 52 x 132) 5 and 13 can be extracted leaving the result as :- 5 x 13 √ 2 = 65√ 2
132/52 weeks in year = 2.54 years ( about 2 1/2 years)
factors of 52 are 1,2,4,13,27 so 52 has 5 factors thats wrong this is right, 1 and 52, 2 and 26, 4 and 13. Those are all of the factors of the number 52.
52. [82 + 22 = 104 ÷ 2 = 52]
1, 2, 4, 13, 26, 52 1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, 132
The GCF of 52 and 132 is 4.
The GCF of 70, 82, and 132 is 2.
The Least Common Multiple (LCM) for 52 132 is 1,716.
LCM(52, 82) = 2132.
The Least Common Multiple (LCM) for 52 36 132 is 5,148.
First three answers are: 32 + 42 = 52 62 + 82 = 100 = 102 52+122 = 132 but there may be more options. Thanks Mohammed Haque
Find the prime factors of 8450. These are 2 x 52 x 132 We can then write, √ 8450 = √ (2 x 52 x 132) 5 and 13 can be extracted leaving the result as :- 5 x 13 √ 2 = 65√ 2
The factors of 82 are 1, 2, 41 and 82.As a product of its prime factors: 2*41 = 82
The LCM is 1716.
x2 + y - 52 = 30x2 - x2 + y - 52 + 52 = - x2 + 30 + 52y = -x2 + 82Since a = -1, the parabola open downward, and crosses the x-axis at x = +&- sq.root of 82.0 = -x2 + 820 - 82 = -x2 + 82 - 82-82 = -x282 = x2+&- sq.root of 82 = x
68.64 percent.