8,16,24,32,40,48,56,64
1, 2, 3, 4, 6, 8, 12, 24
They are elements of the infinite set of numbers of the form 120*k where k is an integer.
Let the first number be ( x ) and the second number be ( y ). According to the problem, we have the equations ( y = x + 6 ) and ( x + y = 22 ). Substituting the first equation into the second gives ( x + (x + 6) = 22 ), which simplifies to ( 2x + 6 = 22 ). Solving for ( x ) yields ( x = 8 ), so the first number is 8 and the second number is ( 8 + 6 = 14 ).
4+6+8+9+10=37
first number +3 2nd number +2
1, 2, 3, 4, 6, 8, 12, 24
4, 8, 12, 166, 12, 18The LCM is 12.
They are elements of the infinite set of numbers of the form 120*k where k is an integer.
Let the first number be ( x ) and the second number be ( y ). According to the problem, we have the equations ( y = x + 6 ) and ( x + y = 22 ). Substituting the first equation into the second gives ( x + (x + 6) = 22 ), which simplifies to ( 2x + 6 = 22 ). Solving for ( x ) yields ( x = 8 ), so the first number is 8 and the second number is ( 8 + 6 = 14 ).
6 and 12 are the first two
What element has 2 electrons in the first shell and 8 in the second and 6 in the third
Well, you first start with number 6 note then repete. Then do a -6 note then 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 7 -9 -9 8 7 -8 7
4+6+8+9+10=37
first number +3 2nd number +2
First 3 composite numbers: 4+6+8 = 18 and 18/3 = 6 which is the average number
The number that completes the sequence would be 11. Imagine the sequence as two sequences of every other number starting with the first 2 and the first 6. You would have 2 3 6 and 6 8 12 2 3 6 is adding odd numbers starting with one. 6 8 12 is adding even numbers starting with two. The next number belongs to 2 3 6 so you would add 5 to get 11.
It is the number 4, 6, 2, 8946465, the you on the frame, and the 875394656+65++7+6+5+6++++++++++++++++++54546+5469+8+8+