Since the lowest common multiple of 9 and 2 is 18, all of the common multiples of 9 and 2 are multiples of 18. The first five are: 18, 36, 54, 72, 90 Since 9 is odd thean there are going to be odd numbers, which are not multiples of two.
There is only one LCM, so it cannot be A lcm, but possibly THE lcm. The LCM of any two (or more) numbers MUST be a multiple of all the numbers. For 15 and 18 the LCM must be a multiple of both 15 and 18. In particular it must be one of the multiples of 18. 18 is an even number, so all its multiples will be even. 145 is an odd number, so it cannot be a multiple of 18 Thus 145 cannot be a multiple of both 15 and 18. Thus it cannot be the LCM of 15 and 18. QED.
No, 6, 12, 18, 24...are even numbers that are multiples of 3.
Also, any multiples of 18 that differ by 18, like 36 and 54.
In order to have a common multiple, you need to be talking about two or more numbers. The question only asked about one number, 18, so there is no correct answer.
The result is not a multiple of two if the sum is odd That is, if one die is odd and the other is even That is, die 1 is odd and die 2 even OR die 1 is even and die 2 is odd. There are 18 such combinations So 18 out of a total of 36 = 18/36 = 1/2 So the probability is 0.5 or 50%
Since the lowest common multiple of 9 and 2 is 18, all of the common multiples of 9 and 2 are multiples of 18. The first five are: 18, 36, 54, 72, 90 Since 9 is odd thean there are going to be odd numbers, which are not multiples of two.
18 2*9 =18
I can think of a couple that would work. Like 99. 9+9=18 (multiple of 9), it's odd and has two digits. . The full set is 27 45 63 81 99.
15
18 and 36
the first 2 common multiple of 18 and 32 is 288 and 576
There is only one LCM, so it cannot be A lcm, but possibly THE lcm. The LCM of any two (or more) numbers MUST be a multiple of all the numbers. For 15 and 18 the LCM must be a multiple of both 15 and 18. In particular it must be one of the multiples of 18. 18 is an even number, so all its multiples will be even. 145 is an odd number, so it cannot be a multiple of 18 Thus 145 cannot be a multiple of both 15 and 18. Thus it cannot be the LCM of 15 and 18. QED.
No, 6, 12, 18, 24...are even numbers that are multiples of 3.
The Odd Couple - 1970 Two Men on a Hoarse 5-18 was released on: USA: 7 February 1975
Here is one possible way: 2 * 1.25 2 * 1.5 5 * 2.5 It is a very odd way of doing it because, in so doing, none of the cows will remain alive. Suppose you could partition the 18 cows into 9 odd groups. Now, Odd + Odd = Even Even + Even = Even and Even + Odd = Odd So, Odd + Odd + Odd + Odd + Odd + Odd + Odd + Odd + Odd = 18 => Even + Even + Even + Even + Odd = 18 => Even + Even + Odd = 18 => Even + Odd = 18 => Odd = 18 which is false. Therefore, it is impossible to partition 18 cows into 9 odd groups.
18 and any factor of 18.