x3 - 6x2 + 7x - 2 = x3 - x2 - 5x2 + 5x + 2x - 2
= x2(x - 1) - 5x(x - 1) + 2(x - 1)
= (x - 1)(x2 - 5x + 2)
= (x - 1){x - 0.5*[5 - sqrt(25 - 8)]}){x + 0.5*[5 - sqrt(25 - 8)]}
= (x - 1)(x - 0.4384)(x - 4.5616)
so that the roots are
x = 1
x = 0.4384
and
x = 4.5616
Since there is nothing following, none of them!
(2x - 9)(2x - 9)
It is: 16-20 = -4 which means that the given quadratic expression has no real roots.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is a quadratic polynomial.
1
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
None, it involves the square root of a negative number so the roots are imaginary.
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
A 7th degree polynomial.
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
There are none because the discriminant of the given quadratic expression is less than zero.
Since there is nothing following, none of them!
(2x - 9)(2x - 9)
15j2(j + 2)
It is: 16-20 = -4 which means that the given quadratic expression has no real roots.
x2 + 12x + 32 = (x + 8)(x + 4)