Since there is nothing following, none of them!
It is: 16-20 = -4 which means that the given quadratic expression has no real roots.
(2x - 9)(2x - 9)
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is a quadratic polynomial.
1
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
None, it involves the square root of a negative number so the roots are imaginary.
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
A 7th degree polynomial.
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
There are none because the discriminant of the given quadratic expression is less than zero.
Since there is nothing following, none of them!
It is: 16-20 = -4 which means that the given quadratic expression has no real roots.
15j2(j + 2)
(2x - 9)(2x - 9)
x2 + 12x + 32 = (x + 8)(x + 4)