The frequencies are how often each number appears.
This is easiest to calculate using a tally chart:
n : tally
--+------
2 : |
3 : | | |
4 : | | |
5 : |
6 : | | | |
7 : |
Which is filled in by going along the numbers and adding a tally stroke to the tally of the number as it is encountered. The strokes for each number can then be totalled (usually as an extra column in the tally table above) to give the frequency for each number:
n : frequency
--+------------
2 : 1
3 : 3
4 : 3
5 : 1
6 : 4
7 : 1
--+------------
Σ : 13
By summing the individual frequencies a check can be made that possibly all numbers have been tallied as the total of the frequencies should equal how many numbers there are: there are 13, so the frequencies are probably correct.
the answer is 3
2 3 5 are prime numbers.
It is: 2*(3+4)+1 = 15
4 x (3 + 2) - 1.
-10
It is a pattern. Go up two numbers, go down two numbers.
48
2^2=4 3^2=9 4^2=16
4 + 1 - 2 = 3
the answer is 3
No, the numbers 1,1+2, 1+2+3, 1+2+3+4, 1+2+3+4+5... are triangular numbers.
If it is integers, you have -2, -1, 0, 1, 2 and 3. If rational numbers or irrational numbers or real numbers, there are an infinity of them between -3 and 4.
The numbers on the typical die are 1, 2, 3, 4, 5, and 6.Unity: 1Prime numbers: 2, 3, and 5Composite numbers: 4 and 6
Divide 4 by 2, then multiply by 3 and then add 4
There are 6 numbers total with 3 4's. Then, the odds is ½.
2 3 5 are prime numbers.
It is: 2*(3+4)+1 = 15