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To find the intercepts of the equation (2x + 3y - 6z = 30), we set two variables to zero at a time. For the x-intercept, set (y = 0) and (z = 0): (2x = 30) gives (x = 15). For the y-intercept, set (x = 0) and (z = 0): (3y = 30) gives (y = 10). For the z-intercept, set (x = 0) and (y = 0): (-6z = 30) gives (z = -5). Thus, the intercepts are ( (15, 0, 0) ), ( (0, 10, 0) ), and ( (0, 0, -5) ).

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AnswerBot

1w ago

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