The least 4 factors of 144 are 1, 2, 3, and 4 .
A number is a multiple of 312 if it's a multiple of 3, 8 and 13 at the same time
Yes, 104 is a multiple of four. You can tell by using the divisibility rules : if the last two digits of a number are divisible by four, then the whole number is divisible by four. Now lets go back, in case you don't know, divisibility is simply if a smaller number, like four, can go into a larger number, like 104, perfectly;without having to use decimals.
2,3,5,7pe your answer here...
1050.
You could combine the tests for divisibility by 3 and 4. To test for divisibility by three, add all the digits together and see if they're divisible by three. If necessary, you can keep repeating the addition until you come up with a single-digit number. To test for divisibility by four, take the last two digits. If that two-digit number is divisible by four, then the whole number is. This is because any multiple of 100 is divisible by 4, so only the last two digits matter. Combined, these two tests will allow you to quickly check for divisibility by 12.
1, 2, 3 and 4
1, 2, 4 and 47
A number is a multiple of 312 if it's a multiple of 3, 8 and 13 at the same time
1, 2, 3, and 4 are the least four factors of 144.
780 is divisible by 2 because it's even. 780 is divisible by 3 because its digits total a multiple of 3. 780 is divisible by 5 because it ends in a 0. 780 is divisible by 10 because it ends in a 0.
1, because everything is divisible by 1. 2, because it's even. 3, because the sum of the digits is a multiple of 3. 4, because the last two numbers are a multiple of 4.
Yes, 104 is a multiple of four. You can tell by using the divisibility rules : if the last two digits of a number are divisible by four, then the whole number is divisible by four. Now lets go back, in case you don't know, divisibility is simply if a smaller number, like four, can go into a larger number, like 104, perfectly;without having to use decimals.
1) Durability, divisibility, Acceptability , uniformity
1, 2, 3 and 4
2,3,5,7pe your answer here...
Just knowing the divisibility rules for the first four prime factors (2, 3, 5 and 7) will help find the prime factorizations of a large percentage of the numbers you will encounter. At the very least, dividing your original number by those factors should cut it down to a manageable size. The first thing you do when starting a prime factorization is notice whether the number is even. If it is, you can take out two as a factor. If not, you can skip over it. The same with 3 and 5. If you know they are not factors just by looking at the number, it saves a lot of trial and error.
1050.