(21+53)/2 = 37
halfway between 31 and 37 is (31 + 37) / 2 = 68 / 2 = 34.
There are 30 multiples of 4 between 5 and 125. Simply divide by 4 and solve for the multiples of 1 between 1.25 and 31.25. That is a range of 2 to 31, and there are 30 multiples. (31 - 2 + 1)
1. There are two reasons that will confirm that: 1) Factors of 9: 1,3 and 9 (1 and multiples of 3 but none of the other 2 numbers are multiples of 3) 2) 53 is a prime number (a number that has no factors other than 1 and itself)
The multiples of 2 between 7 and 15 are 8, 10, 12, and 14.
37The answer is 37It is: 37
(21+53)/2 = 37
143 - 37 = 106 106 / 2 = 53 53 + 37 = 90 So your answer is 90. You can also add the two numbers and then divide by two to find the answer: 143 + 37 = 180 180 divided by 2 = 90
They are 53*1, 53*2, 53*3, ... . 53*10 If you need them worked out, I suggest you use the calculator that comes with your computer.
If you multiply 37 by any whole number, you get a multiple of 37 - that's what "multiple" is all about. For example, calculate any of the following, and you get a multiple of 37: 0 x 37 1 x 37 2 x 37 3 x 37 etc., also: -1 x 37 -2 x 37
LCM(1, 2, 3, ... , 100) = 26*34*52*72*11*13*17*19*23*29*31*37*41*43*47*53*59*61*67*71*73*79*83*89*97 = 7284218307581900599279651679808748132800. All common multiples are multiples of this number.
halfway between 31 and 37 is (31 + 37) / 2 = 68 / 2 = 34.
Half way between 53 and 61 is (53 + 61) ÷ 2 = 57(53 + 61) / 2 = 114/2 = 5753+61 / 2114/257 is the answer
37½ of 32 = 37 1/2 × 32 = 75/2 × 32 = 75 × 16 = 1200 37 and (one half of 32) = 37 + ½ × 32 = 37 + 16 = 53
To produce only whole numbers: 1, 2, 37, 74
The prime numbers between 2 and 60 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59
There are 30 multiples of 4 between 5 and 125. Simply divide by 4 and solve for the multiples of 1 between 1.25 and 31.25. That is a range of 2 to 31, and there are 30 multiples. (31 - 2 + 1)