Q: What are the multiples of 6 between 4 and 50?

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Look at the multiples of 6. The smallest and greatest multiples of 6 that can be divided evenly by 4 are 12 and 48. So the common multiples of 4 and 6 up to 50 are 12, 24, 36, and 48.

Since the LCM is 12 then the common multiples are multiples of 12 12, 24, 36, 48

The multiples of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76 and so on. The multiples of 6 are 6,12,18,24,30,36,42,48,52,58,62,66,72,78,84,90,96,102 and so on.

They are: 6 12 18 24 30 36 42 and 48

The possibilities are 2, 4 and 6 which are all multiples of two. So the odds are 50:50

Related questions

Look at the multiples of 6. The smallest and greatest multiples of 6 that can be divided evenly by 4 are 12 and 48. So the common multiples of 4 and 6 up to 50 are 12, 24, 36, and 48.

10

4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.

There are seven multiples of six that fall between one and 50: 12, 18, 24, 30, 36, 42, 48.

Since the LCM is 12 then the common multiples are multiples of 12 12, 24, 36, 48

They are: 54, 60, 66.

They are: 6 12 18 24 30 36 42 and 48

There are 67 multiples of 6 and 50 multiples of 8 in that range. Their total, 117, will include numbers that are both.

5 + 10+15+20=50 ans

Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3

The first 50 multiples of 6 are the first fifty even multiples of 3.

Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72