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Let starting point is 9x,

so next three consecutive multiple of 9 are 9x+9, 9x+18 and 9x+27

This question can't be answered without a given starting point, which has not been specified in the question.

If the starting point is, say, 25 (which is not a multiple of 9, by the way), the next three multiples of 9 would be 27, 36 and 45 (the next three numbers after '25' that are multiples of 9).

But 9, 18, 27, 36, 45, 54, 63, 72, 81, and 90 are the first 10 multiples of 9. one way to know a multiple of 9 is subtract 1 from the number being multiplied by 9 then add to get 9.

for example: 9x7

7-1=6

6+?=9

?=3 answer is 63.

hope this helps! :)

Another way to identify a multiple of 9 is to add together the digits in the number. If the sum of the digits is a number that is evenly divisible by 9, than the original number is also evenly divisible by 9.

for example:

for the number 27: add the digits = 2+7 = 9, so 27 is a multiple of 9

for the number 1,638: add the digits 1+6+3+8=18. If 18 is a multiple of 9 (and it is), so is 1,638.

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Q: What are the next three consecutive multiples of 9?
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